((5x)/x^2-4)0

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Solution for ((5x)/x^2-4)0 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(5*x)/(x^2)-4 > 0

5*x^-1 > 4

5*x^-1 > 4 // : 5

x^-1 > 4/5

1/(x^1) > 4/5

x <> 0

1/(x^1) > 4/5 // * x^2

(x^2)/(x^1) > 4/5*x^2

x^1 > 4/5*x^2

x-4/5*x^2 > 0

x^1*(1-4/5*x) > 0

x < 0

-(abs(x))^1*(4/5*(abs(x))^1+1) > 0 // : -(abs(x))^1

4/5*(abs(x))^1+1 < 0

4/5*(abs(x))^1 < -1 // : 4/5

(abs(x))^1 < -1/4/5

(abs(x))^1 < -5/4 // ^ 1/1

abs(x) < (-5/4)^(1/1)

abs(x) < -5/4

x belongs to the empty set

x < 0

x > 0

x^1*(1-(4/5*x^1)) > 0 // : x^1

1-(4/5*x^1) > 0

1 > 4/5*x^1 // : 4/5

1/4/5 > x^1 // ^ 1/1

(1/4/5)^(1/1) > x

x in (0:5/4)

x > 0

x in (0:5/4)

x in (0:5/4)

(0:5/4)

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